Question

How many solutions does 2x + 3y = 7 and 6x + 5y = 11 have

Answer 1

Step-by-step explanation:

It will have a unique solution.

bcoz a1/a2 is not equals to b1/b2

Hope it will help u....

Answered by :<<<Miss Aakhiraa>>>

Answer 2

$\tt SOLUTION:- \\ \\ \sf \small 2x + 3y = 7 \: \: ....(1) \\ \\ \sf 6x + 5y = 11 \: \: ....(2) \\ \\ \tt Multiplying \: eq \: (1) \: by \: 3 \\ \\ \sf \small \therefore 6x + 9y = 21 \: .....(3) \\ \\ \tt Subtracting \: eq \: (2) \: from \: (3) \\ \\ \sf 6x + 9y = 21 \\ \sf \small \underline {</p><p>-(6x + 5y = 11) } \\ \\ \sf \implies 4y = 10 \\ \\ \sf y = \frac{10}{4} \\ \\</p><p>\sf \red{\boxed{y = \frac{5}{2}}} \\ \\ \tt substituting \: y = \frac{5}{2} \: in \: eq \: (1) \\ \\ \sf 2x - 3(\frac{5}{2}) = 7 \\ \\ \sf 2x - \frac{15}{2} = 7 \\ \\ \sf 2x = 7 - \frac{15}{2} \\ \\ \sf 2x = \frac{14 - 15}{2} \\ \\ \sf 2x = -\frac{1}{2} \\ \\</p><p>\sf x = - \frac{1}{4} \\ \\ \\</p><p>\texttt{It has one pair of solution}} \\ \\ \tt that \: is \: (x,y) = (-\frac{1}{4},\: \frac{5}{2})$