Question

How many solutions does the pair of equations y = 0 and y = -5 have?​
Can I have an explanation?

Answer 1

0

Step-by-step explanation:

First, we will write down our equations in y=mx+c form

so,

1) y=0 => y=(0)x+(0) (i)

2)y=(-5) => y=(0)x+(-5) (ii)

so by these equations we can say

by equations (i) and (ii) :-

slope is 0 for both.

constant of (i) is 0

constant of (ii) is (-5)

(NOTE->"here those constants which determine the intersection point of the line with the y axis are called as ordinates of the line")

hence,

the lines will be perpendicular to y axis at their ordinates

and if we find their abscissas(x-coordinate of the point where the lines cuts the x axis) will be 0 for both the lines as putting y=0(as its cutting the x axis) in (i) and (ii),they will give x=0 for both the equations.

so,

y=0 will be a perpendicular line to y axis (m=0) at (0,0), and

y=(-5) will be a perpendicular line to y axis (m=0) at (0,-5).

as both the lines are perpendicular to the same line, both the initial lines will be parallel to each other.

hence making the lines never meet

I.e. solution of lines = 0