how many solutions does the pair of linear equation x+2y-1=0 and x-y=3 have
Answers
Answer:
Answer:
System of equation has infinite solution.
Step-by-step explanation:
Given system of linear equation are:
x+2y-3=0x+2y−3=0
\frac{1}{2}x+y -\frac{3}{2}=0
2
1
x+y−
2
3
=0
We will check by
if \frac{a_1}{a_2}\neq\frac{b_1}{b_2}
a
2
a
1
=
b
2
b
1
then unique solution.
if \frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}
a
2
a
1
=
b
2
b
1
=
c
2
c
1
then infinite solution.
if \frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2}
a
2
a
1
=
b
2
b
1
=
c
2
c
1
then no solution.
Now,
\frac{1}{\frac{1}{2}}=\frac{2}{1}=\frac{-3}{-\frac{3}{2}}
2
1
1
=
1
2
=
−
2
3
−3
2=2=22=2=2
Hence, system of equation has infinite solution.
Step-by-step explanation:
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Answer:
infinitely many solutions
Step-by-step explanation:
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