Math, asked by brieshaffer, 11 months ago

How many solutions exist for the given equation?

0.75(x + 40) = 0.35(x + 20) + 0.35(x + 20)

zero
one
two
infinitely many

Answers

Answered by anu1152
11
one only

Bcoz it is a linear equation in x
linear equation has degree 1.. So no of solutions also 1

anu1152: for a quadratic equation, no of solutions is
anu1152: 2 ....
anu1152: Hope it helps
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Answered by harendrachoubay
7

One solution exists.

Step-by-step explanation:

We have,

0.75(x+40)=0.35(x+20)+0.35(x+20)

To find, number of solutions exist = ?

0.75(x+40)=0.35(x+20)+0.35(x+20)

0.75x+30=0.35x+7+0.35x+7

0.75x+30=0.7x+14

0.75x-0.7x=14-30

0.05x=-16

x=\dfrac{-16}{0.05}

Hence, one solution exists.

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