Question

How many solutions exist for the given equation? 12x + 1 = 3(4x + 1) – 2 zero one two infinitely many

Answer 1

12x+1=3(4x+1)-2
12x+1=12x+3-2
12x+1=12x+1

Since the above equation will always be true i.e. X ka value kuchh v le lo ye sahi hoga
so it has infinite number of solns.
done.
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Answer 2

12x + 1 = 3(4x+1) -2

12x + 1= 12x +3 -2

12x + 1 =12x + 1

In view of the fact that the above equation will always be true that is the value of x can be taken as per the choice.

So, the given equations can have infinite number of solutions.