Question

How many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1

Answer 1

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How many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1
The above equation is a linear equation as the highest power of x is 1. So the equation has only one solution.
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Answer 2

Answer:

The no solution  is  possible

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question  3x + 13 = 3(x + 6) + 1

Arrange the equation in RHS side multiplying 3 into (x+6)+1

[tex]3x+13=3x+18+1\\ 3x+13=3x+19[/tex]

We have find the value of" x" in the above question.

Here we will use the transposition method.

Hence, for solving the above equation, we will solve it by separating the like terms at one side to another side,

So, we will shift 13 from LHS to RHS the sign will change from positive to negative ,

So, we will shift 3x from RHS to LHS the sign will change from positive to negative ,

As we get,

$3x+13=3x+19$

[tex]3x-3x=19-13\\ [/tex]

Hence no solution is possible