Question

How many solutions of the equation 3y-1=y+3 are there on the Cartesian plane?
1 point
One
Many
Infinitely many
Two​

Answer 1

Answer:

$\huge{\underline{\underline{Given→}}}$

• $\sf\green{Equation→3y-1=y+3}$

$\huge{\underline{\underline{To\:Find→}}}$

$\sf\purple{→How\:many\:solutions\:are\:there\:for\:the\:given\:equation.}$

$\huge{\underline{\underline{Answer→}}}$

$\sf\blue{→3y-1=y+3}$

$\sf\blue{→3y=y+3+1}$

$\sf\blue{→3y-y=3+1}$

$\sf\blue{→2y=4}$

$\sf\blue{→y=\frac{4}{2}}$

$\sf\blue{→y=2}$

$\sf{\boxed{\boxed{\pink{→y=2✔}}}}$

$\bold{\underline{\underline{Conclusion→}}}$

$→$ So from here, we get that there is one and only one solution of the given equation.

$→$ Hence option a)$\sf{\underline\color{steelblue}{one}}$ is the required answer.

HOPE IT HELPS.