Math, asked by Jacob65, 4 months ago

How many solutions The following system of equations has? y = x and y = 2x

Answers

Answered by itzmesweety
11

Answer:

Write a system of equations to model the situation. Add the equations to eliminate the y-term and then solve for x. Substitute the value for x into one of the original equations to find y. Check your answer by substituting x = 8 and y = 2 into the original system.

Answered by GopalS
1

Answer:

Exactly one solution (unique) which is (0,0).

Step-by-step explanation:

Given, y=x, we can rewrite as x-y=0, now a1=1, b1=-1

      y=2x, we can rewrite as 2x-y=0, now a1=2, b1=-1

So, a1/a2 not equal to b1/b2.

So, they have exactly one solution (unique) which is (0,0).

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