Math, asked by jasspuwar13453, 4 months ago

how many solutions these pair of equations x-4y-6=0and 3x-4y-6=0 will have ​

Answers

Answered by dibyangshughosh309
25

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 \tt{x - 4y - 6 = 0 }\\  \tt{3x - 4y - 6 = 0}

 \huge{ \red{ \underline{  \underline{ \mathfrak{ \color{orange}{answer}}}}}}

 \blue{x =  \frac{1}{2}}  \\ \blue{ y =  - 22}

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 \tt{x - 4y = 6.......(i) }\\  \tt{3x - 4y = 6.....(ii)}

 \tt{on \: subtracting\: equation \: (i) \: from \: (ii) \: we \: get}

 \tt{3x -  \cancel{4y} = \cancel{ 6}} \\  \tt{x -  \cancel{4y} =  \cancel{6} }\\  -  \:   \: \:  \:  \: \:  \:  \:  \:  +  \:  \:  \:  \:  \:  \:  \:  -  \\  -  -  -  -  -    -  -  -  \\  \tt{ \to2x = 0 }\\ \tt {\red{ \to x =  \frac{1}{2} }}

 \tt{on \: putting \: x =  \frac{1}{2} on \: equation \: (i) \: we \: get}

 \tt{ \to \: x - 4y = 6 }\\ \tt{ \to  \frac{1}{2}  - 4y = 6 }\\   \tt{ \to\frac{1}{2}  - 6 = 4y} \\   \tt{ \to\frac{1 - 12}{2}  = 4y} \\  \tt{ \to4y =  \frac{ - 11}{2}}  \\ \tt{ \to y =  \frac{ - 11}{ \cancel{ {2}}^{1} }  \times  \cancel {{4}}^{2} } \\  \tt{ \to \: \red { y =   - 22}}

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