Question

How many spherical bullets can be made out of a lead cylinder 15 cm high and with base ridus 3 cm, each bullet being 5 mm in diameter?

Answer 1

$volume \: of \: cylinder = \pi {r}^{2} h \\ = \pi {3}^{2} \times 15 \\ = \pi135 {cm}^{3} \\ now \: volume \: of \: sphere = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi \times { \frac{5}{10} }^{3} \\ = 0.167 {cm}^{3} \\ now \\ number \: of \: bullet \: = \frac{volume \: of \: cylinder}{ volume \: of \: sphere} \\ = \frac{135\pi}{0.167\pi} \\ = 809$
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Answer 2

Answer:

6480

Step-by-step explanation:

Height of cylinder = 15 cm

radius of cylinder = 3 cm

Volume of cylinder = $\pi r^2 h$

                                = $3.14 \times 3^2 \times 15$

                                = $423.9 cm^2$

Diameter of spherical ball = 5 mm

10 mm = 1 cm

So, 1 mm = 0.1 cm

So, 5 mm = 0.5 cm

radius of spherical ball = 0.5/2 =0.25 cm

Volume of sphere = $\frac{4}{3} \pi r^{3}$

                              = $\frac{4}{3}\times 3.14 \times 0.25^{3}$

                              = $0.0654166666667$

No. spherical balls can be made = $\frac{423.9}{0.0654166666667}=6480$

So, 6480 spherical balls can be made .