how many spherical bullets each of 5cm in diameter can be cast from a rectangular block of metal 11dm*1m*5dm?
Answers
Answer:
Number of bullets = 8400.
Step-by-step explanation:
Given : Spherical bullets each of 5 cm in diameter can be cast from a rectangular block of metal 11 dm*1 m*5 dm.
To find : How many spherical bullets were there ?
Solution :
First we convert the dimensions into one dimension i.e, cm,
So, The dimensions of the cuboid is
The volume of the cuboid is
Now we have given the diameter of Bullet is 5 cm.
Radius
Volume of the bullet is
Therefore, Number of bullets = 8400.
Answer:
8400
Step-by-step explanation:
11×10=110cm
1×100=100cm
5×10=50cm
So, The dimensions of the cuboid is 110 \times 100 \times 50cm110×100×50cm
The volume of the cuboid is
V=110 \times 100 \times 50cmV=110×100×50cm
Now we have given the diameter of Bullet is 5 cm.
Radius r=\frac{5}{2}cmr=
2
5
cm
Volume of the bullet is
v=\frac{4}{3}\pi r^3v=
3
4
πr
3
v=\frac{4}{3}\frac{22}{7}(\frac{5}{2})^3v=
3
4
7
22
(
2
5
)
3
\text{Number of bullets} = \frac{\text{volume of cuboid}}{\text{volume of one bullet}}Number of bullets=
volume of one bullet
volume of cuboid
\text{Number of bullets} =\frac{110 \times 100 \times 50}{ \frac{4}{3}\times \frac{22}{7} \times\frac{5}{2} \times\frac{5}{2} \times\frac{5}{2}}Number of bullets=
3
4
×
7
22
×
2
5
×
2
5
×
2
5
110×100×50
\text{Number of bullets} =110\times 100\times 50 \times\frac{3}{4} \times\frac{7}{22}\times\frac{2}{5}\times\frac{2}{5} \times\frac{2}{5}Number of bullets=110×100×50×
4
3
×
22
7
×
5
2
×
5
2
×
5
2
\text{Number of bullets} =8400Number of bullets=8400
Therefore, Number of bullets = 8400.