How many spherical lead balls of radius 2.1cm can be obtained from a rectangular solid lead with dimension 88cm,42cm and 21cm?
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Answered by
5
convert all the values in cm to m.
let n be the number of balls formed. n*volume of small lead ball = (V1+V2+V3)
n*4/3πr^3=4/3π(r1^3+r2^3+r3^3)
n*4/3*22/7*2.1*2.1*2.1=4/3*22/7*(88*88*88+44*44*44+21*21*21)
n*9.261=681472+85184+9261
n*9.261=775917
n=775917/9.261
n=83783.28
n is approximately equal to 83783
therefore 83783 lead balls can be made of radius 2.1cm
let n be the number of balls formed. n*volume of small lead ball = (V1+V2+V3)
n*4/3πr^3=4/3π(r1^3+r2^3+r3^3)
n*4/3*22/7*2.1*2.1*2.1=4/3*22/7*(88*88*88+44*44*44+21*21*21)
n*9.261=681472+85184+9261
n*9.261=775917
n=775917/9.261
n=83783.28
n is approximately equal to 83783
therefore 83783 lead balls can be made of radius 2.1cm
Answered by
0
Step-by-step explanation:
sphere of diameter is equal to 4.2 and sphere of radius equal 2.1 .
volume of Sphere is =4/3×2.1×2.1×2.1×22/7
volume of cuboid =66×42×21
number of shote is equal to volume of solid cube by divided by volume of 1 spherical shot .
= 66×42×21×3×7/4× 2.1×2.1×2.1
= 1500 cm cu...
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