Math, asked by ultron38, 9 days ago

How many spherical solid bullets can be made out of a solid cube of lead whose edges measures 44 cm, each bullet being 4 cm in diameter ?​

Answers

Answered by pandaXop
198

Number of Bullets = 2541

Step-by-step explanation:

Given:

  • Measure of edges of solid cube is 44 cm.
  • Diameter of bullet is 4 cm.

To Find:

  • How many spherical solid bullets can be made from that cube ?

Solution: Let x bullets can be made. To find out x, we need to find volume of cube and spherical bullet.

Volume of Cube = a³

\implies{\rm } Vol. = 44 × 44 × 44 cm³

\implies{\rm } 85184 cm³

So the volume of solid cube is 85184 cm³.

Now radius of bullet = Half of diameter

  • Radius = 4/2 = 2 cm

Volume of Sphere = 4/3πr³

\implies{\rm } Vol. = 4/3 × 22/7 × 2³

\implies{\rm } 88/21 × 8 cm³

\implies{\rm } 704/21 cm³

  • Number of bullets = Vol.(cube/bullet)

➙ x = 85184/704/21

85184 × 21/704

➙ 121 × 21 = 2541

Hence, 2541 spherical bullets can be made out of that solid cube.

Answered by Anonymous
208

Answer:

 \large \dag Question :-

How many spherical solid bullets can be made out of a solid cube of lead whose edges measures 44 cm, each bullet being 4cm in diameter.

 \large \dag Answer :-

 \sf\tt\large{\red {\underline {\underline{⚘\;Number \;of \;bullets:}}}}

 \sf\tt\large{\red {\underline {\underline{\;= \;2541 \;bullet's:}}}}

 \large \dag Solution :-

Hey mate .

First let verify your questions and next enter to calculations.

In the question given that the spherical solid cube of lead whose edges measures 44 cm ,each bullet being 4cm in diameter.

According to the given questions we should find the how many spherical solid bullets can be made.

So,

First we should calculate its volume .

Here we know the formulae to find volume of bullet that is ,

 \sf\tt\large{\red {\underline {\underline{⚘\;Volume \;of \;bullet \;=:}}}}

 \frac{4}{3} \pi \:  {r}^{3}

Now applying all the values we get,

  • Volume of bullet =4/3×22/7×2^3

  • Volume of bullet =4×22×8/3×7

Now ,

 \sf\tt\large{\red {\underline {\underline{⚘\;Volume \;of \;cube \;= \;S^3:}}}}

  • The Volume of cube =44^3.

Which can also be written as,

  • Volume of cube =44×44×44.

Now,

▪We should find number of bullet's

▪To find This we know that,

Number of bullet's=

  • Volume of bullet/ volume of spherical bullet.

Number of bullet's =

  • 4×22×8/3×7/44×44×44

Number of bullet's =

  • 44×44×44×3×7/4×22×8

Number of bullet's =2541 bullet.

▪Therefore,

 \large \dag This is the perfect answer to your question.

Hope it helps u mate.

Thank you .

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