Math, asked by 1sharmamithlesh, 2 months ago

How many sqare tiles of side 6 CM are required for a floor of length 54 cm and length 40 cm? cost of each tile is rupees 50 what is the total required cost?

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Answers

Answered by ankushrathour2004
2

Step-by-step explanation:

How many square tiles of a side does 40 cm need to build a room of length 16 m and breadth 10 m?

lets try this again…

wall area would be (16m +10m +16m +10m) * 2.44m

or 52 by 2.44 = 126.88m.sq.

(assume rectangular room with height of about 8ft, or 2.44m)

tile area is 0.4m.sq. or 0.4 by 0.4 = 0.16m.sq.

number of tiles (round up for breakage)…

= 793 ->> 800+ tiles

note each corner would involve about 12 tiles (six tall by two) * 4 corners

= 48 tiles total being cut or whatever

so double the tile number for the corners

and take the approximate total to 850 tiles just for the walls

And then there’s the floor…

16m by 10m is 160m.sq.

divide 160 by 0.16 is 1000 tiles

and if all cuts and fitting are careful and correct —

maybe add 5% to 10% so 1050 to 1100 tiles for the floor

there would also need to be an adjustment for grout lines, but whatever

Answered by rajeshkrsah65
1

Answer:

Step-by-step explanation:

area of floor =l*b=54*40=2160cmsq

area of tiles=6*6=36cmsq

tiles needed=area of floor/ area of tiles

                    =2160/36=60tiles

cost of 1 tiles =50rupees

cost of 60 tiles=60*50=3000ruppes

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