How many square glazed tiles of side 8 cm will be
required to cover the walls of a room 4 m by 3 m by 2 m? If 25 tiles cost Rs 40, find the cost of tiling the walls of the room.
Answers
Answer: The no. of tiles required is 4375 and the cost is Rs 7000
Step-by-step explanation:
Given dimensions of the room = 4 m* 3 m* 2 m (400 cm * 300 cm * 200 cm)
Given dimensions of the tile = 8 cm
Area of the four walls of the cuboid= 2h(l+b)
= 2*200(400+300)
= 280000 cm^2.
Area of one tile= 8*8= 64 cm^2
Therefore, no. of tiles required= 280000/64= 4375.
Given cost of 25 tiles= Rs 40
Therefore, cost of one tile= Rs 1.6.
No of tiles= 4375
Therefore, total cost= 4375*1.6
= Rs 7000
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Answer:
Step-by-step explanation:
Given dimensions of the tile = 8 cm
Area of one tile= 8*8= 64 cm^2
Given dimensions of the room = 4 m* 3 m* 2 m (400 cm * 300 cm * 200 cm)
Area of the four walls of the cuboid= 2(l+b)*h
= 2*200(400+300)
= 280000 cm^2.
Therefore, no. of tiles required= 280000/64= 4375.
Given cost of 25 tiles= Rs 40
No of tiles= 4375
Therefore, total cost= 4375/25
=125*40
=rs 7000