how many square tiles (20 cm ×20 cm )are needed to coat the side and base of pool a pool which is 10 m long,6 meters and 3 m deep
Answers
Step-by-step explanation:
Given:
- Size of tiles
- Dimentions of the pool
To Find:
- Required number of tiles
Solution:
Area of base= length × Breadth=10×6=60m^2
Area of the sides=2(l+b)×h
=2(10+6)×3
=2×16×3
=96 m^2
Total area to be tiles=60+96=156m^2=1560000cm^2
Area of each tile=side×side=20×20cm^2=400cm^2
Required number of tiles
=Total area/area of each tile
=1560000/400
=3900 tiles ANS
Solution -
The dimensions of the given pool are -
• Length : 10 m
• Breadth : 6m
• Height : 3m .
We need to find the number of square tiles required to coat the base and side of this pool , given the dimensions of each tile .
For this, we need to first find the lateral surface of the pool .
LSA of any cuboid in general
> 2( l+b ) h
> 2 × 16 × 3
> 96 m².
Note that from the LSA, we only got the area of the walls of the pool. The base isn't included in this .
Now , the area of the base of the pool :
> Length × Breadth
> 60m².
Total area to be tiled thus becomes 156 m².
Each tile has a dimension of 20cm × 20 cm
> 400 cm².
We need to convert this to metre square and divide the total area by this .
10000 cm² = 1 m²
> Dimension of the tile is 0.04 m².
Number is tiles needed :
> 156/0.04
> 3900 tiles.
This is the required answer .
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