Question

How many square tiles each of side 0.5 m will be required to pave the floor of a room which is4m long and 3m broad?

Answer 1

48 tiles are required to pave the floor of a room which is4m long and 3m broad

Step-by-step explanation:

Length of floor = 4m

Breadth of floor = 3m

Area of floor = $Length \times Breadth = 4 \times 3 = 12 m^2$

Side of square tile = 0.5 m

Area of square tile = $Side^2 = 0.5^2=0.25 m^2$

So, No. of tiles required to cover the floor =$\frac{12}{0.25}=48$

Hence 48 tiles are required to pave the floor of a room which is4m long and 3m broad

# learn more:

A tile measure 10*10cm how many such tiles are required to cover a wall of 4m*2.5m

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Answer 2

Answer:

48 tiles are required to pave the floor of a room which is4m long and 3m broad

Step-by-step explanation:

Length of floor = 4m

Breadth of floor = 3m

Area of floor =

Side of square tile = 0.5 m

Area of square tile =

So, No. of tiles required to cover the floor =

Hence 48 tiles are required to pave the floor of a room which is4m long and 3m broad