How many square tiles of side 10cm each are required to cover the floor of a
kitchen having length 9 m and breadth 9 m respectively.
Answers
Answered by
0
The area of the floor is 9*9=81m^2
Area of each tile=0.1*0.1=0.001m^2
(Bcz 10cm is 0.1m)
So no of tiles required=area of floor divided by area of each tile
So no of tiles required are
81/.001=81000
(No means number)
Answered by
0
Answer:81 TILES ARE NEEDED
Step-by-step explanation:
area of tile =10cm*10cm
=100 sqcm =1 sqm
area of kitchen floor =9m*9m
=81 sqm
number of tiles required =area of tile *area of floor
=1*81
=81
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