How many square tiles of side 16cm will be required to pawe the floor of a rectangular room 6.4*5m?
Answers
Step-by-step explanation:
area of floor = 6.4*5
= 32 m*m = 32*100*100 = 320000cm*cm
area of square tile =
16*16
256cm*cm
no of tiles required= 320000/256
=1250 tiles
Given:-
- Side of square titles (a)= 16cm
- Length of rectangular room,l = 6.4 m
- Breadth of rectangular room ,b = 5m
To Find:-
- No. of square tiles (n)
Solution:-
Firstly we have find the area of rectangular room and after that we calculate the area of each tiles .
According to the Question
→ Area of rectangular room = Length×Breadth
Substitute the value we get
→ Area of room = 6.4×5
→ Area of room = 32m²
∴ The area of rectangular room is 32m²
Now Calculating the area of each square tiles
→ Area of square tiles = (side)²
Substitute the value we get
→ Area of square tiles = 16²
→ Area of square tiles = 256cm²
∴ The area of each tiles is 256cm²
Converting the cm² into m²
→ 1m² = 10000cm²
∴ 256cm² = 256/10000m² = 0.0256m²
Now Calculating the Number of tiles
→ No.Of tiles = Area of room/Area of each tiles
Substitute the value we get
→ n = 32/0.0256
→ n = 32×10000/256
→ n = 320000/256
→ n = 1250 tiles
∴ The total no.of tiles required to pawe the floor is 1250 tiles.