how many square tiles of side 18 cm will be required to pave the floor of a rectangular room 7.2 ×5.4m ?
Answers
Answered by
50
Hi ,
length of the each square tile = a = 18 cm
dimensions of the rectangular room are
length = l = 7.2 m = 7.2 × 100 cm = 720cm
breadth = b = 5.4m = 5.4 × 100cm = 540cm
let number of times
required to pave the floor = n
n = ( area of the floor ) / ( area of the each tile )
n = ( lb ) / a²
n = ( 720 × 540 ) / ( 18 × 18 )
n = 40 × 30
n = 1200 tiles required .
I hope this helps you.
:)
length of the each square tile = a = 18 cm
dimensions of the rectangular room are
length = l = 7.2 m = 7.2 × 100 cm = 720cm
breadth = b = 5.4m = 5.4 × 100cm = 540cm
let number of times
required to pave the floor = n
n = ( area of the floor ) / ( area of the each tile )
n = ( lb ) / a²
n = ( 720 × 540 ) / ( 18 × 18 )
n = 40 × 30
n = 1200 tiles required .
I hope this helps you.
:)
Answered by
19
area of square tile is =18*18= 324cm^2
area of rectangular room is= 720 cm * 540. cm= 388800cm^2
number of square tiles= 388800/324=1200
hope this is helpful to you plz mark it as brainliest
area of rectangular room is= 720 cm * 540. cm= 388800cm^2
number of square tiles= 388800/324=1200
hope this is helpful to you plz mark it as brainliest
AMAYTRIPATHI:
plz mark my answer as brainliest
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