Question

how many square tiles of Side 2 metre it will I need to cover a floor of length 8 meters and breadth 7 metre​

Answer 1

Answer :-

• 14 square tiles of side 2 m will be needed to cover a floor of length 8 metres and breadth 7 metres.

Given :-

• Side of square tiles = 2 m.
• Length of the floor = 8 m.
• Breadth of the floor = 7 m.

To find :-

• The number of square tiles needed to cover the floor.

Step-by-step explanation :-

• In this question, we have to find out how many square tiles of side 2 m will be needed to cover a floor of length 8 metres and breadth 7 metres.

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Let's find the area of one square tile first!

• The tile is in the shape of a square, as given in the question.

We know that :-

$\underline{ \boxed{\sf Area \: of \: a \: square = Side \times Side}}$

Here,

• Side = 2 m.

Hence,

$\boxed{\tt Area \: of \: one \: tile = 2 \times 2}$

Multiplying 2 with 2,

$\overline{ \boxed{\tt Area \: of \: one \: tile = {4 \: m}^{2}} }$

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Now, let's find the area of the floor!

• The floor is in the shape of a rectangle, since it's length and breadth is given.

We know that :-

$\underline{ \boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}$

Here,

• Length = 8 m.
• Breadth = 7 m.

Hence,

$\boxed{\tt Area \: of \: the \: floor = 7 \times 8}$

Multiplying 7 with 8,

$\underline{ \boxed{\tt Area \: of \: the \: floor = {56 \: m}^{2} }}$

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Now finally, let's find the number of tiles needed to cover the floor!

$\underline{ \boxed{\sf No. \: of \: tiles \: needed = \dfrac{Area \: of \: the \: floor}{Area \: of \: one \: tile}}}$

Here,

• Area of the floor = 56 m².
• Area of one tile = 4 m².

Hence,

$\boxed{\tt No \: of \: tiles \: needed = \dfrac{56}{4}}$

Dividing 56 by 4,

$\overline{\boxed{\tt No \: of \: tiles \: needed =14.}}$

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• Hence, 14 tiles will be needed to cover the floor of length 8 metres and breadth 7 metres.