how many square tiles of side 25 CM will be required to cover the floor of a corridor which is 8 metre long and 6m broad
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Answered by
13
Answer:
area of rectangle =l*b
given
length= 8m
breadth=6m
8m=800cm
6m=600cm
area of rectangle=l*b
=800*600
=4,80,000
area of tiles
25*25=625sqcm
4,80,000/625=768
Therefore number of tiles required=768
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Answered by
9
Length=8 meter= 800cm. And. Breadth=6meters=600cm
Area of one tile= side x side= 25x25=625
We know area of rectangle= Length x Breath= 800 x 600
=4,80,000
To find number of tiles that can be filled= 4,80,000 divided by 625= 768.
Therefore the number of tiles that can be fit is 768.
Area of one tile= side x side= 25x25=625
We know area of rectangle= Length x Breath= 800 x 600
=4,80,000
To find number of tiles that can be filled= 4,80,000 divided by 625= 768.
Therefore the number of tiles that can be fit is 768.
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