Question

How many square tiles with dimension 5 cm can be fixed in a small surface whose length is 40 cm and breadth is 25 cm.

Answer 1

Area of floor = 40×25 = 1000 sqcm

Area of tiles is 5×5=25 sqcm

No of tiles = 1000/25 = 40 nos

Answer 2

40 tiles are required

Step-by-step explanation:

Side of square tile = 5 cm

Area of square tile = $Side^2 = 5^2 = 25 cm^2$

Length of floor = 40 cm

Breadth of floor = 25 cm

Area of floor = $Length \times Breadth = 40 \times 25 = 1000 sq.cm.$

No. of tiles required =$\frac{\text{Area of floor}}{\text{Area of tile}}$

No. of tiles required =$\frac{1000}{25}$

No. of tiles required = 40

Hence 40 tiles are required

#Learn more:

How many tiles whose length and breadth are 13 cm and 7 cm respectively are needed to cover a rectangular region whose length and breadth are 520 cm and 140 cm?

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