Question

how many square tiles with dimension 5cm can be fixed in a small surface whose length is 40 cm and breadth is 25 cm.

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

40 tiles

Step-by-step explanation:

Dimension of tile = 5 cm

Length of the surface = 40 cm

Breadth of the surface = 25 cm

So, total area that needs to be covered = total area of the surface = L x B

= (40  x 25) $cm^{2}$   = 1000 $cm^{2}$

now, area of 1 tile =  $(side)^{2}$

= $(5cm)^{2}$  = 25 $cm^{2}$

Now, total number of tiles needed = \frac{\textrm{ total area that needs to be covered}}{\textrm{ area of 1 tile}}

= $\frac{1000 cm^{2} }{25 cm^{2} }$  = 40

Hence, 40 tiles are needed to cover the area completely.