How many squares of side 5 cm are required to cover a rectangular floor measuring 25 m by 10 m ?
Answers
Answer:
answer is 10 bro.
l×b = 25×10= 250
side² = 5×5 = 25
250/25 = 10
Answer:
1,00,000 squares will be required to cover the rectangular floor.
Step-by-step explanation:
Given Information:
The length of the rectangular floor (L) = 25 m
The breadth of the rectangular floor (B) = 10 m
The side of the square (a) = 5 cm = 0.05 m
To Be Calculated:
The number of squares required to cover the rectangular floor.
Solution:
At first, we evaluate the area of the rectangular floor,
So, the area of the rectangle is given by the product of length and breadth = Length × Breadth = 25 × 10 = 250
Now, the area of the square is given by the square of the side of the square = Side × Side = 0.05 × 0.05 = 0.0025
Now, to evaluate the number of squares required to cover the rectangular floor is Area of the rectangle/ Area of the square = 250/0.0025 = 100000
Therefore, 100000 squares will be required to cover the rectangular floor.
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