Math, asked by aguptapsy, 4 months ago

How many squares on the co-ordinate plane exist with one vertex at P(–1, 1) and having atleast one of the coordinate axes as axis of symmetry?

Answers

Answered by wangarwarprajakta5c2
1

I know it

The questions answer is 7

Answered by SuvadipSingha
1

Step-by-step explanation:

Input:points[] = {(0, 0), (0, 2), (2, 0), (2, 2), (1, 1)}

Output: 1

Explanation:

As the points (0, 0), (0, 2), (2, 0), (2, 2) forms square which is parallel to the X-axis and Y-axis, Hence the count of such squares is 1.

Input:points[] = {(2, 0), (0, 2), (2, 2), (0, 0), (-2, 2), (-2, 0)}

Output: 2

Explanation:

As the points (0, 0), (0, 2), (2, 0), (2, 2) forms one square, whereas points (0, 0), (0, 2), (-2, 0), (-2, 2) forms other square which is parallel to the X-axis and Y-axis,

Hence the count of such squares

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