Math, asked by ronaldo2286, 1 year ago

how many stones with upper face dimensions 10 cm × 15cm will required to lay a path that 25m long and 12 m with

Answers

Answered by karthickshiva1015
6

Answer:

20000 stones

Step-by-step explanation:

The area of one stone = length x breadth

                                      = 10 x 15

                                      = 150 cm²

Area of the path = length x breadth

                            = 25 x 12

                            = 300 m²

1 m² = 100 x 100

       = 10000 cm²

300 m² = 300 x 10000

             = 3000000 cm²

Total no. of bricks = 3000000 ÷ 150

                               = 20000 stones

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