Question

how many structures in the list given below have (22+x) chromosome ? polar body, Oogonia, primary oocyte, ovum secondary oocyte​

Answer 1

Answer:

Spermatogenesis is the process of formation of spermatid (n) from spermatogonia(2n). The process goes as follows:-

Spermatogonia(2n)⟶ Primary Spermatocyte(2n)⟶2 Secondary Spermatocyte(n)⟶4 Spermatid(n)

Oogenesis is the production of an ovum from oogonia. The mechanism, in short, can be depicted as below:-

Oogonia(2n)⟶ Primary Oocyte(2n)⟶ Secondary Oocyte(n)+ Polar Body(n)

This meiosis I is an unequal division leading to the formation of a haploid ovum and a polar body. The first polar body is said to be atretic and does not divide further. However, the secondary oocyte completes its meiosis during fertilization to form an egg(n) and the second polar body(n).

So, 50 secondary oocytes produce 50 ovum and 50 secondary spermatocytes produce 100 sperms.

So the correct answer is A.

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Answer 2

Answer:

Three structures in the list given have (22 + X) chromosomes. They are namely, polar body, ovum, and secondary oocyte.

Explanation:

• Oogonia have a ploidy of 2n which means, 44+XX. After maturation, it becomes a primary oocyte which also has a ploidy of 2n and the condition still remains 44 + XX.
• In primary oocytes, after the first meiosis, it gives a secondary oocyte along with the first polar body. Both are haploid having n ploidy.
• The secondary oocyte undergoes second meiosis forming an ovum with n ploidy and a condition of 22 +X. The second polar body will also be haploid having a condition of 22 + X.

Hence, the polar body, ovum, and secondary oocyte are 22 + X (Haploid)

Oogonium and primary oocyte are 44 + XX (Diploid)

Therefore, three structures in the list given have (22 + X) chromosomes.