Question

How many such digits are there in the number 5236978 each of which is as far away from the beginning of the number as when the digits are rearranged in ascending order within the number? Select one: a. More than three b. Three c. None d. Two e. One

Answer 1

Answer:

The number is , 5236978

Number   position

5               =1

2               =2

3               =3

6              =4

9             =5

7             =6

8             =7

Now, when number arranged in ascending order, the number becomes , 2356789

Number      Position

2                  =1

3                 =2

5                  =3

6                 =4

7                 =5

8                =6

9                =7

As, in both the cases , number 6 occupies 4 th position.

Option e : One

Answer 2

Given : 5236978

Digits arranged in ascending order within the number​

To Find : How many such digits are there in the number 5236978 each of which is as far away from the beginning of the number as when the digits are rearranged in ascending order within the number​

Solution:

5236978

5   -  0   away

2   -  1   away

3   - 2  away

6     3  away

9     4   away

7      5    away

8      6    away

5236978 arranged n ascending order

2356789

2  -  0   away

3   -  1   away

5   - 2  away

6     3  away

7    4   away

8      5    away

9      6    away

5236978

2356789

There are only one such digit  6  in the number 5236978 each of which is as far away from the beginning of the number as when the digits are rearranged in ascending order within the number​

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