Math, asked by neil56, 1 year ago

how many sulphur atoms are present in 2.5mole of h2so4

Answers

Answered by bruno44
0
One sulfuric (H2SO4) molecule has 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms.

You can also say one mole of sulfuric acid has two mols of hydrogen atoms, 1 mol of sulfur atoms, and 4 moles of oxygen atoms.

So in total, we have 7 mols of atoms. But that's in 1 mol of sulfuric acid. In two mols of sulfuric acids we have 14 mols of atoms.

How much is a mol? That's the Avogadro's constant = 6.022 x 10^23

So the answer is 14 x 6.022 x 10^23 = 8.43 x 10^24 atoms

Answered by rishi1803
3
since no. of atoms present in H2SO4= no. of moles × avogadros no.

= 2.5 × 6.022 × 10²³

= 15.055 × 10²³ atoms

now no. of sulphur atoms= no. of atoms × 10²³× 1 ( since there is only one sulphur atom in H2SO4)

= 15.055 ×10²³× 1

=15.055 ×10²³ atoms

hope this helps
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