How many tablets each containing 8.75 grains of mercuric chloride will be required to make parts of 0.5 solution?
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Answer:
One tablet containing 8.75 grains of mercuric chloride will be required to make parts of 0.5 solution
Explanation:
Mercuric chloride contains 8.75 grains
- To eliminate excess Sn2+ during the measurement of iron, mercuric chloride was used.
- Stannous chloride reduces ferric ion to ferrous ion in an acidic medium when estimating the iron from a particular solution.
- By reacting with either mercury or mercury(I) chloride, chlorine produces mercuryc chloride.
- A hot, concentrated solution of mercury(I) compounds and hydrochloric acid can also be used to create it.
4.375 gr. in 1 fl ounce = 1% w/v solution
Mercuric chloride = 4.375
4.375 gr × 0.05 = 0.2187 gr required to get 1 fl .oz 0.05%
0.2187gr × 40 = 0.8748 grain solution required to get 40 fl. 0z 0.05%
8.75 gr/8.75 gr = 1 tablets
Therefore, one tablet is required to prepare one quart of 0.05% solution
Final answer:
One tablet containing 8.75 grains of mercuric chloride will be required to make parts of 0.5 solution
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