Question

How many term are identical in the two a.p. if each of the a.p. 3,5,7,and 4,7,10,....... is continued to 100 terms? ...​

Answer 1

Answer:

201 both can be continued

Step-by-step explanation:

a equals to first term of first AP and a two equal to the first term of second a p t = 2 difference between first AP and d2 equals to difference between first and second term of second AP n = 100 in both

a=3

a2=4

d=2

d2=3

n=100

an=a+(n-1)d. (1)

an=a2+(n-1)d2. (2)

from (1)and(2) we get,

a+(n-1)d=a2+(n-1)d

3+(100-1)2=4+(100-1)3

3+99*2=4+99*3

201=301

= 201comes in both of a. p