Question

how many term are identical in the two A.p. if each of the A.P. 3,5,7,and 4,7,10,....... is continued to 100 terms? ...

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Answer 1

SOLUTION

If we write both the series upto few terms, 3+5+7+9+11+13+15+17+19+...

4+7+10+13+16+19+22+25+...

=It is noted that,

3rd,6th,9th,12th... terms of first series and 2nd, 4th, 6th, 8th terms of second series are identical.

=But, one thing must be kept in mind that the last term of first series is going to be less than that of the last term of second series.

=so, the first series would end at the last identical term or a number next to it.

=so the no. of identical terms will be simply calculated as,

100/3= [33.33]= 33

Since the no. of identical terms will be an integer.

hope it helps

Answer 2

33 is the Answer.............

see attachment......