Question

How many term are there in a arithmetic sequence with a common different of 4 and with firts and last term 3 and 59 respectively

Answer 1

Answer:

formula

an = a + (n-1 ) d

here an = nth term = 59

a = first term given 3

d = common difference given 4

and n is no of terms. we have to find out

hence

59 = 3 + (n-1) 4

56 = (n-1) 4

14 = n-1

n = 15 ans.

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