How many term of the A.P. 2,6,10.....are needed to make the sum 288
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Answered by
1
a = 2
d = 4
Sn = 288
=> n/2 [ 2a + (n-1) d] = 288
=> n[ 2×2 + (n-1) 4] = 576
=> n[ 4 + 4n - 4]
=> n × 4n = 576
=> 4n^2 = 576
=> n^2 = 144
=> n = 12
Required number of terms = 12
d = 4
Sn = 288
=> n/2 [ 2a + (n-1) d] = 288
=> n[ 2×2 + (n-1) 4] = 576
=> n[ 4 + 4n - 4]
=> n × 4n = 576
=> 4n^2 = 576
=> n^2 = 144
=> n = 12
Required number of terms = 12
Answered by
2
a = 2
d = 4
an = n/2(2a+(n-1)d)
288 = n/2(2*2+(n-1)4)
288 = 2n(1+(n-1))
So, n(square) = 288/2
n = root(144)= 12
12 terms are necessary
d = 4
an = n/2(2a+(n-1)d)
288 = n/2(2*2+(n-1)4)
288 = 2n(1+(n-1))
So, n(square) = 288/2
n = root(144)= 12
12 terms are necessary
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