How many term of the A.P. 2,6,10.....are needed to make the sum 288
MegaRayquaza16:
r u retarded or something?
Answers
Answered by
0
Heya !!
==================================
A.P. 2, 6, 10, …
a = 2
d = 6-2 = 4
Sn = n/2 [ 2a + (n-1) d ]
288 = n/2 [ 2(2) + (n-1) 4 ]
=> 2×288 = n ( 4 + 4n - 4 )
=> 576 = n (4n)
=> 576 = 4n²
=> n² = 576/4
=> n² = 144
=> n = √144
=> n = 12
Hence, 12 terms are needed to give the sum 288.
==================================
Hope my ans.'s satisfactory.☺
==================================
A.P. 2, 6, 10, …
a = 2
d = 6-2 = 4
Sn = n/2 [ 2a + (n-1) d ]
288 = n/2 [ 2(2) + (n-1) 4 ]
=> 2×288 = n ( 4 + 4n - 4 )
=> 576 = n (4n)
=> 576 = 4n²
=> n² = 576/4
=> n² = 144
=> n = √144
=> n = 12
Hence, 12 terms are needed to give the sum 288.
==================================
Hope my ans.'s satisfactory.☺
Answered by
0
Solution:
_____________________________________________________________
Given:
AP: 2, 6 , 10,...
∴ a =2,
∴ d = 6-2 =4,
&
_____________________________________________________________
To find:
The value of n,.
_____________________________________________________________
We know that,
=>
=>
=>
=>
=>
=>
As, number of terms can't be negative,.
=> ∴ n = + 12,..
_____________________________________________________________
=> Hope it Helps !!
_____________________________________________________________
Given:
AP: 2, 6 , 10,...
∴ a =2,
∴ d = 6-2 =4,
&
_____________________________________________________________
To find:
The value of n,.
_____________________________________________________________
We know that,
=>
=>
=>
=>
=>
=>
As, number of terms can't be negative,.
=> ∴ n = + 12,..
_____________________________________________________________
=> Hope it Helps !!
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