Question

how many term of the ap 22,20, 18 shoud be taken so that their sum is zero​

Answer 1

Answer:

n=12

Step-by-step explanation:

given

$\frac{n}{2} \times (2a + (n - 1)d) = 0$

a=22

d=-2

Hence

$\frac{n}{2} \times (22 + (n - 1) \times - 2) = 0$

Solving we get

$n(11 + (n - 1) \times - 1) = 0$

$11 - n + 1 = 0$

$n = 12$

Answer 2

Answer:

The answer is 23.

Step-by-step explanation:

Let the number of terms be n,

So, sum = n/2{ 22×2+(n - 1) (-2)

or, 0= n{46 - 2n}

or, n= 23.