how many terms are in a.p 102;108;114..........936.find sum of all these terms
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a = 102
d = 108 - 102 = 6
aₙ = 936
aₙ = a + (n - 1) d
936 = 102 + (n - 1) * 6
834 = 6n - 6
840 = 6n
n = 140
₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋
Sₙ = n/2 (2a + (n - 1) d)
= 140/2 (204 + 139 * 6)
= 72660
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