Question

How many terms are in an arithmetic sequence whose first term is -3, common difference is 2 and the last term is 29? Show your solution

Answer 1

Answer:

Given that,

First term = -3

Common difference = 2

Last term = 29

To find: n = ?

According to the general term formula of an AP, we know that:

→ aₙ = a + (n-1) d

→ 29 = (-3) + (n-1) (2)

→ 29 + 3 = ( n - 1 ) ( 2 )

→ 32 = 2 ( n - 1 )

→ 32/2 = ( n - 1 )

→ 16 = ( n - 1 )

→ 16 + 1 = n

→ n = 17

Hence the number of terms in the arithmetic sequence is 17.

Answer 2

Answer:

$\huge \mathtt {answer}$

According to Formula of an AP = AP = a + (n -1) d

$29 = - 3 + (n \: - 1) \times 2$

$29 + 3 = (n \: - ) \: (2)$

$32 = 2 \: \: (n \: - 1)$

$\frac{32}{2} = (n - 1)$

$16 = (n \: - 1)$

$16 + 1 = n$

$n \: = 17$

$\bf \: arthimetical \: sequence \: = 17$