Question

how many terms are in the AP 6, 3, 0, - 3.......-36​

Answer 1

Answer:

d= -3

a=6

Tn=-36

Tn=a+(n-1)d

-36=6+(n-1)-3

-42=(n-1)-3

-42/-3=n-1

14=n-1

n=15

Answer 2

Answer:

Solution

Step-by-step explanation:

a=6

common difference (d)= a2-a1

=3-6

d = -3

An = -36

an =a+(n-1) d

-36=6+(n-1) -3

-36-6 +(n-1) -3

-42=(n-1) -3

-42/-3=(n-1)

14=n-1

14+1 = n

n=15