Question

how many terms are in the series :4,7,10,13,............148?

Answer 1

hello..


please refer the above attachment.
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thank you...

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Answer 2

Common difference = d = 7 - 4 = 3
First term = a = 4

$a_{n} = a + (n - 1)d \\ \\ \\ 148 = 4 + (n - 1)3 \\ \\ \\ 148 - 4 = (n - 1)3 \\ \\ \\ 144 = (n - 1)3 \\ \\ \\ \frac{144}{3} = n - 1 \\ \\ 48 = n - 1$

48 + 1 = n

49 = n

Hence, there are 49 terms.

I hope this will help you

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