How many terms are in the series 96 48 24 12 ...3/16
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a=96,. r=1/2
tn=3/16
the given series is in geometrical progression
tn=a*r^n-1
3/16=96*1/2^n-1
1/2^n-1=3/16*96
=1/16*32
=1/2^9
2^n-1=2^9
n=9+1=10
there are 10 terms
tn=3/16
the given series is in geometrical progression
tn=a*r^n-1
3/16=96*1/2^n-1
1/2^n-1=3/16*96
=1/16*32
=1/2^9
2^n-1=2^9
n=9+1=10
there are 10 terms
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4
There are 10terms........
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