Question

how many terms are there between 150 and 750 which are divisible by both 3 and 6​

Answer 1

Step-by-step explanation:

First number between 105 and 750 divisible by 6 (a1) =108

Second number between 105 and 750 divisible by 6 (a2)= 114

so let it be n numbers between 105and 750 which are divisible by 6

Common difference (d)= 114–108

d=6

Last number between 105 and 750 which is divisible by 6 (an) = 744

an=a1+(n-1)d

744=108+(n-1)6

744–108=(n-1)6

636=(n-1)6

636=6n-6

636+6=6n

642=6n

642/6=n

n=107

so there are 107 numbers between 103 and 750 which are divisible by 6

Hope its help