how many terms are there in A.P. 201,208,215,................,369?
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Let the number of terms be n, it means let there are n terms.
First term = a
= 201
Common Difference = d
= any term - previous term
= 215 - 208 = 208 - 201
= 7
Last term = n th term
=
= 369
We know,
369 = 201 + ( n - 1 )( 7 )
369 - 201 = ( n - 1 ) 7
168 = ( n - 1 )7
168 / 7 = n - 1
24 = n - 1
24 + 1 = n
25 = n
Therefore,
Number of the terms present between the given AP is 25.
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