Math, asked by mahek2003, 1 year ago

how many terms are there in A.P. 201,208,215,................,369?

Answers

Answered by lucky1829
6
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Answered by abhi569
20

Let the number of terms be n, it means let there are n terms.



First term = a

                 = 201


Common Difference = d

                 = any term - previous term

                 = 215 - 208 = 208 - 201

                 = 7


Last term = n th term

                = a_{n}

                = 369



We know,


a_{n} = a+(n-1)d

369 = 201 + ( n - 1 )( 7 )

369 - 201 = ( n - 1 ) 7

168 = ( n - 1 )7

168 / 7 = n - 1

24 = n - 1

24 + 1 = n

25 = n



Therefore,

Number of the terms present between the given AP is 25.

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