Question

how many terms are there in an A.P . 187 , 194 , 201 , ...........439?

Answer 1

it's 37
tn=a+(n-1)d
439=187+(n-1)7
439-180
259=7n
n=37
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Answer 2

Given:

An A.P . 187 , 194 , 201 , ...439

To Find:

How many terms are there in the AP?

Solution:

An arithmetic progression is a progression in which every consecutive term differs by a common difference which is denoted by d and the first term of an AP is denoted by a.

The given AP is 187, 194, 201, ...439

So here the,

first term a=187

common difference d=194-187

                                   =7

So now the number of terms can be found out by knowing the nth value for the last term using the formula,

$T_n=a+(n-1)d$

So now put the values for the last term that is,

[tex]T_n=a+(n-1)d\\ 439=187+(n-1)7\\ 252=(n-1)7\\ n-1=36\\ n=37[/tex]

So the number of terms is 37.

Hence, the number of terms in the AP is 37.