How many terms are there in AP 4,-1,-6.....-106
Answers
Answered by
13
hey friend
here
a=4
and d=-5
an=-106
an=a+(n-1)d
4+(n-1)-5=-106
4-5n+5=-106
-5n+9+106=0
-5n=-115
n+115/5=>23
hope it helps you
here
a=4
and d=-5
an=-106
an=a+(n-1)d
4+(n-1)-5=-106
4-5n+5=-106
-5n+9+106=0
-5n=-115
n+115/5=>23
hope it helps you
Bharath2151:
tq
Answered by
22
Hey friend, ☺️ here is your answer ___________________________
First term, a1 = 4
Second term, a2 = - 1
Common difference, d = a2 - a1 = - 1 - 4 = - 5
Last term, an = - 106
an = a1 + (n - 1)d
-106 = 4 + (n - 1)*-5
-106 = 4 - 5n + 5
-106 = 9 - 5n
-5n = - 106 - 9
-5n = - 115
n = 23
Total number of terms = 23
Hope this helps you..
First term, a1 = 4
Second term, a2 = - 1
Common difference, d = a2 - a1 = - 1 - 4 = - 5
Last term, an = - 106
an = a1 + (n - 1)d
-106 = 4 + (n - 1)*-5
-106 = 4 - 5n + 5
-106 = 9 - 5n
-5n = - 106 - 9
-5n = - 115
n = 23
Total number of terms = 23
Hope this helps you..
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