how many terms are there in ap 7,16,25,....349
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The number of terms in the given AP = n = 39
Explanation:
Given AP = 7,16,25,....349
First term = a = 7
Common difference = d = a₁ - a₂
= 16 - 7
= 9
Last term = nth term = aₙ = 349
By the formula, we have
aₙ = a + (n – 1) d
Substituting the values, we get:
= 349 = 7 + (n -1) 9
⇒ 349 - 7= 9 (n-1)
⇒ 342 = 9 (n-1)
⇒ n-1 = 342/9
⇒ n-1 = 38
⇒ n = 38 + 1
⇒ n = 39
Hence, the number of terms = n = 39
Hope you understood.
Thank You.
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