Question

how many terms are there in ap32,34,34...40​

Answer 1

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$ap \: 32,34,34...40$

$this \: is \: not \: an \: ap \\ as \: it's \: difference \: between \: the \\ terms \: is \: not \: constant .$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$

Answer 2

Given:-

ap32,34,34...40

is not an ap

If the question is ap32,34,36...40

then,

$a_1 =32 \\ a_2= 34$

${\:\: \:} d = a_2 - a_1$

${\:\: \:} d = 34-32$

${\:\: \:} d = 2$

${\:\: \:} a_n=40$

$\LARGE {\pink {\fbox {\color {purple} {Solution}}}}$

$\tt{\green{a_n = a + (n-1 ) d}}$

$\tt{40 = 32 + (n-1 ) 2}$

$\tt{40 - 32 = (n-1 ) 2}$

$\tt{\frac{(40 - 32)}{2} = (n-1 ) }$

$\tt{\frac{8}{2} = n-1 }$

$\tt{4 = n-1 }$

$\tt{4+1 = n }$

$\tt{5 = n }$

$\tt{\pink{\therefore n=5 }}$