Question

How many terms are there in arithmetic sequence 7,11,15.......139?

Answer 1

Answer:

34

Step-by-step explanation:

AP : 7 , 11 , 15 ,... 139

a = 7 , d = 11 - 7 = 4 , n = ?

Last term = 139

Tn = 139

a + (n - 1)d = 139

7 + (n - 1)4 = 139

(n - 1)4 = 139 - 7

(n - 1) = 132/4

n - 1 = 33

n = 33 + 1

n = 34

Hence,

There are 34 terms in Given AP.

I HOPE IT'S HELPFUL:)