how many terms are there in between 100 and 600 divisible by 8?
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Answer:
a=104, d=8 and l= 600
let n be the no. of terms
therefore, l=a+(n-1)d
600= 104+(n-1)8
600-104=(n-1)8
496/8=n-1
62=n-1
n=62+1
n= 63
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